1.3x^2-5x=0

Solution for 1.3x^2-5x=0 equation:

1.3x^2-5x=0

a = 1.3; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·1.3·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*1.3}=\frac{0}{2.6}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*1.3}=\frac{10}{2.6}
=3+1/1.1818181818182
$